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BEΔ$T$ Sсhrödinger
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BEΔ$T$ Sсhrödinger
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meir 10 Apr, 2018 @ 4:45am 
{\displaystyle i\hbar {\frac {\partial }{\partial t}}\Psi ({\vec {r}},t)=\left[-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}+V({\vec {r}},t)\right]\Psi ({\vec {r}},t).}

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Founded
6 November, 2016